Perl's lack of 'in' keyword

[Paul Makepeace]

On Thu, Oct 9, 2008 at 11:51 AM, Andy Armstrong <andy at hexten.net> wrote:
> On 9 Oct 2008, at 01:39, Iain Barnett wrote:
>>
>> if $a ~~ $b     #this could mean several things
>
> A smart match between two scalars. Clear.
>
>> if $a in $b             #it is clear what this means
>
> One scalar is in another? WTF?

>>> "ass" in "assume"
True

>> if a in b               #this is even better IMO
>
>
> Dunno what a and b are - so who knows what it does?

>>> fun = ("beer", "buffy", "pie", "perl")
>>> "perl" in fun
True

Because you write your language so that the commonly understood
meaning of the keyword is manifested in its implementation?

> Which is not, of course, to say that you're wrong - but that readability is
> - to some extent - in the eye of the beholder.
>
> --
> Andy Armstrong, Hexten
>
>
>
>