Assigning anonymous hash to a list
Hernan Lopes
hernanlopes at gmail.com
Wed Jul 31 02:32:55 BST 2013
When you do that, you are implicitly saying:
The thing on the left is equals the thing in the right.
So, in the left you have 1 thing ( a list because of parenthesis ),
and on the right, you have 2 things: string+object.
Add parenthesis on the right and transform it into a list.
After that perl will understand you are assinging the first thing on
the list (from left) equals the first thing on the list (from right)
and so on.
[]'s
Hernan Lopes
On 7/30/13, gvim <gvimrc at gmail.com> wrote:
> Can anyone explain why this works:
>
> my $ref = {a => 1, b => 2, c => 3};
> say $ref->{b}; # Result: 2
>
> ... but this doesn't :
>
> my ($str, $ref) = 'text', {a => 1, b => 2, c => 3};
> say $ref->{b}; # Result: Use of uninitialized value
>
> Seems a little inconsistent.
>
> gvim
>
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