print (1 ? 1 : 0) . 'x'

[O'Shaughnessy, Jamie]

print (1 ? 1 : 0) . 'x';

What do you expect this would print?

I expected the output would be "1x" - the ?: evaluates to 1, the ()s are needed because . Is higher precedence than ?: so you end up with 1 . 'x' as the parameter to print - hence print "1x".

However it doesn't, it just prints "1".

Can anyone explain what is happening here?

Changing the code to:

print (1 ? 1 : 0), 'x';

Also does the same, yet:

Print 1 ? 1 : 0, 'x';

Does print out "1x".

Also, taking the original code and assigning it to a variable:

my $x = (1 ? 1 : 0) . 'x';
print $x;

Also prints out "1x"

???

Cheers,
Jamie