Regex to match odd numbers
Jasper
jaspermccrea at gmail.com
Tue May 27 17:08:16 BST 2014
Something like the prime regex would work:
('1' x $foo) =~ /^(11)*1$/
On 27 May 2014 16:43, Joel Bernstein <joel at fysh.org> wrote:
> Surely you only need to examine the right-most digit to know if the number
> is odd? Your special requirement to (AIUI) consider 0..7 as even isn't
> difficult to add.
>
> /joel
>
>
> On 27 May 2014 16:22, David Cantrell <david at cantrell.org.uk> wrote:
>
> > As part of the nasty mess that is CPANdeps, I have this line of code:
> >
> > $record->{is_dev_perl} = (
> > $record->{perl} =~ /(^5\.(7|9|11|13|15|17|19|21)|rc|patch)/i
> > ) ? 1 : 0;
> >
> > I'd like to not have to remember to add 23 to the list in a year or so's
> > time. Can anyone think of a nice way of matching any odd number from 7
> > upwards? Obviously it's easy to do in a coupla lines of perl code
> > instead of a regex, so I'm asking more out of curiosity than because I
> > actually need it.
> >
> > --
> > David Cantrell | Official London Perl Mongers Bad Influence
> >
> > Today's previously unreported paraphilia is tomorrow's Internet sensation
> >
> >
>
--
Jasper
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